The Answer to Columbo’s Puzzle

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I almost forgot to give you the answer to Columbo’s puzzle.

To recap: You have three bags filled with gold pieces, but the pieces in one of the bags are counterfeit. The only way you can tell the difference is that the genuine gold pieces weigh a pound apiece, but each counterfeit piece weighs one pound and one ounce. You need to discover which bag contains the counterfeits: but all you have, by way of equipment, is an old-fashioned penny scale, like they used to have in drugstores, and a single penny. How do you do it?

Well, no one here came up with the answer, so here it is.

From Bag #1 take one piece; from Bag #2, take two pieces; and from #3, three.

Weigh all six pieces at once.

If it weighs six pounds, one ounce, the counterfeits are in Bag 1. If it weighs six pounds, two ounces, they’re in Bag 2; if six pounds, three ounces, Bag 3.

Don’t feel bad. Columbo had help from his screenwriters.

9 comments on “The Answer to Columbo’s Puzzle

  1. I’d thought of taking individual coins out of the bags, but I was counting on the penny scale being the kind that would adjust itself downward if part of the object on the scale was removed, so we could tell when the extra ounce disappeared as the coins were knocked off the scale one by one. Those scales were rare, though, and I was too lazy to look up when and where they were used. Anyway, I would never have thought of Columbo’s solution.

  2. May I edit your response a tad please.

    In the original question proposed from the suspect to Columbo
    he proposed as you said, the gold pieces were a pound apiece.
    the counterfeits, weighed differently, it us unkown higher or lower.

    It is Columbo, in his restating the puzzle, who assigns an INCREASE of 1 OUNCE to the puzzle.

    Your solution still works in this scenario.

    Warm regards.

  3. In the original puzzle he said you could have as many pieces as you imagine in the bags so what if you only imagined one piece in each bag as I did when he first introduced the puzzle?

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